1.1. The mininum number of cards to be dealt from an arbitrarily shuffled deck of 52 cards, to guarantee that three cards are from some same suite is:
(a) 3 (b) 8 (c) 9 (d) 12
Explanation (answer at the end):
This is a standard cards problem, and the solution is quite easy. First of all, there are 4 suites in a deck of cards (usually called Spades, Clubs, Hearts and Diamonds, though several other names also have been given to them). Each suite has 13 cards in it.We want a guarantee that three cards from the same suite come to us, we shall assume the worst case and ensure 3 cards of same suite occur even in that case.
The worst case here is that, as we pick cards, each card is of a different type. In that case, with the first 4 picks, we'd have taken one card of each suite. With the next 4 cards, we'd have 2 cards of each suite. Now, if we pick another card, whatever suite it may be, we have 2 other cards of that suite already. So, we now have 3 cards of the same suite, which was our objective!!
So, from the above, it's clear that to guarantee that three cards are from some same suite, we have to pick 9 cards from the deck.
Answer: (c)
1 comment:
good explanation da sundu.. you will make a better professor :)
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